H(t)=5t^2+10t+20

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Solution for H(t)=5t^2+10t+20 equation: 



(H)=5H^2+10H+20

We move all terms to the left:

(H)-(5H^2+10H+20)=0

We get rid of parentheses

-5H^2+H-10H-20=0

We add all the numbers together, and all the variables

-5H^2-9H-20=0

a = -5; b = -9; c = -20;
Δ = b2-4ac
Δ = -92-4·(-5)·(-20)
Δ = -319
Delta is less than zero, so there is no solution for the equation

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